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Read a power with x in its base and its exponent as an exponential for the Risch-Norman ansatz - #2044
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…r the Risch-Norman ansatz Rubi's 2.3 x^(-2 - 1/x) (1 - ln(x)) is (-x^(-1/x))', and was declined, where e^(-ln(x)/x) (1 - ln(x))/x^2 is answered by the Risch-Norman ansatz at once: the ansatz's monomials are exponentials and logarithms, and a power with x in its base and its exponent is neither as written. B^E is e^(E ln(B)) on the principal branch, which is what the power means. The ansatz now reads it so, keeping the part of the exponent free of x as a power of B, since e^((-2 - 1/x) ln(x)) is a monomial with no polynomial in x beside it, and x^(-2) e^(-ln(x)/x) is a rational function of x times one. The answer is written back as a power, with the factors written on both sides of the bar cancelled: -x^(-1/x), Rubi's. Part of #233. Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
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Closing as redundant: #2034, merged since this branch was cut from 78cd31b, already answers both rows on master 49bf5d1 with the same answers ( 🤖 Generated with Claude Code |
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Part of #233.
x^(-2 - 1/x) (1 - ln(x))is(-x^(-1/x))', and was declined. Spellede^(-ln(x)/x) (1 - ln(x))/x^2, the ansatz answers it at once. Its monomials are exponentials and logarithms, and a power with x in both base and exponent is neither as written.B^Eise^(E ln(B))on the principal branch, which is what the power means, and the ansatz now reads it so. The part of the exponent free of x stays a power ofB:e^((-2 - 1/x) ln(x))is a monomial with no polynomial in x beside it, whilex^(-2) e^(-ln(x)/x)is a rational function of x times one.-x^(-1/x), Rubi's own, where the ansatz alone gave-x e^(-ln(x)/x)/x.Chain against master 78cd31b:
The full unit suite passes locally: 16,551 passed, 0 failed. The BREAKING-CHANGES lengths were measured on the branch. Rebased onto 49bf5d1.
🤖 Generated with Claude Code
https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura