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Lower the power of a binomial beside x below a sine before splitting over its roots - #2051
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Rafael-SOWNet merged 1 commit intoOct 22, 2026
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…over its roots Rubi's 4.1.11 sin(c + d x)/(x (a + b x^3)^3) was declined: the split over x and the cube's three roots, each to the third power, came out past the size it hands on. Since a + b x^n - b x^n is a, 1/(x Q^k) is 1/(a x Q^(k - 1)) - (b/a) x^(n - 1)/Q^k, and each of the two is a question SolveATrigonometricOfALinearOverAPowerOfALinear answers: the first lower in k until the split takes it, the second over Q^k without x. Where the direct split declines, the two are asked as questions of their own. Part of #233. Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
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Part of #233.
sin(c + d x)/(x (a + b x^3)^3)was declined.SolveATrigonometricOfALinearOverAPowerOfALinearsplits over the linears of the denominator, which here are x and the cube's three roots, each to the third power. That split came out past the size it hands on. Over the square of the binomial it answers, in 6,403 characters.a + b x^n - b x^nisa,1/(x Q^k)is1/(a x Q^(k - 1)) - (b/a) x^(n - 1)/Q^k, forQ = a + b x^nwith n three or four. Each of the two is a question the rule answers: the first is lower in k, until the split takes it, and the second is overQ^kwithout x. Only where the direct split declines are the two asked as questions of their own.sin(c + d x)/(x (a + b x^3)^3)cos(c + d x)/(x (a + b x^3)^3)Rubi's own answer is a sum over the cube's roots of sine and cosine integrals, as this one is.
Chain against master ef4150e:
The library builds for netstandard2.0, net8.0 and net10.0. The suite is left to CI. The BREAKING-CHANGES lengths were measured on the branch, and the 2.5.0 column on a v2.5.0 build. Rebased onto de11aaf.
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https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura