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Ask a hyperbolic quotient over a linear in its cosine as the cosine's, before the tangent - #2053
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Rafael-SOWNet merged 1 commit intoOct 22, 2026
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…, before the tangent Rubi's 6.2.5 sech(x)^3/(a + b cosh(x)) and 6.5.3 sech(x)^4/(a + b sech(x)) ran past the corpus's budget. SolveARationalFunctionOfTheHyperbolicTangent answered each under the tangent of the half argument, a cube of 1 + t^2 beside a symbolic quadratic, in about 118,000 characters. By Osborn's rule each is a rational function of a cosine alone over a sum linear in it, which partial fractions in the cosine answer: 1/(cos(s)^3 (a + b cos(s))) is 2,121 characters. A third mode of SolveAHyperbolicIntegrandAsATrigonometricOne asks that question beside #2042's, ahead of the tangent, only where s stands in cos(s) alone and the sums below the bar are linear in it, to the first power: over the square of one, written out, 6.7.1's (a + b cosh(x))/(b + a cosh(x))^2 took four times the memory in s. The answer in s goes back as the rule writes every one, and is checked by its derivative. Part of #233. Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
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Part of #233.
sech(x)^3/(a + b cosh(x))and 6.5.3sech(x)^4/(a + b sech(x))ran past the corpus's budget.SolveARationalFunctionOfTheHyperbolicTangentanswered each under the tangent of the half argument, as a cube of1 + t^2beside a symbolic quadratic, in about 118,000 characters.1/(cos(s)^3 (a + b cos(s)))comes to 2,121 characters. A third mode ofSolveAHyperbolicIntegrandAsATrigonometricOneasks that question beside Ask a hyperbolic quotient over a quadratic in its sine or cosine as the sine's, before the tangent #2042's, ahead of the tangent. It applies only where s stands incos(s)alone and the sums below the bar are linear in it, to the first power. The answer in s goes back as the rule writes every one, and is checked by its derivative.(a + b cosh(x))/(b + a cosh(x))^2. Its denominator is a square written out, and asked in s it took 0.60 GB where the tangent takes 0.14, confirmed alone. Hence the sums must now be linear, and 971 is back at master's 0.136 GB.sech(x)^3/(a + b cosh(x))sech(x)^4/(a + b sech(x))cosh(x)^3/(a + b cosh(x))cosh(x)^2/(a + b sech(x))The answers spell the tangent of the half argument through
tan(-i x/2), as the Osborn rule's other answers do.Chain against master ef4150e, re-run after the narrowing:
The library builds for netstandard2.0, net8.0 and net10.0. The suite is left to CI. The BREAKING-CHANGES lengths were measured on the branch, and the 2.5.0 column on a v2.5.0 build. Rebased onto 79754e7.
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https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura