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following sql reports Exception: DataFusion error: type_coercion caused by Execution error: Cannot access field at argument 1: type Utf8 is not Struct, Map, or Null #1796

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@l1t1
s="""
WITH RECURSIVE
  input(sud) AS (
    VALUES('....754..........8.8.19....3....1.6........34....6817.2.4...6.39......2.53.2.....'), 
    ('3.........5.7.3..8....28.7.7......43...........39.41.54..3..8..1...4....968...2..')
  ),
  digits(z, lp) AS (
    VALUES('1', 1)
    UNION ALL SELECT
    CAST(lp+1 AS TEXT) as z, lp+1 as lp FROM digits WHERE lp<9
  ),
  x(s, ind) AS (
    SELECT sud, instr(sud, '.') FROM input
    UNION ALL
    SELECT
      substr(s, 1, ind-1) || z || substr(s, ind+1),
      instr( substr(s, 1, ind-1) || z || substr(s, ind+1), '.' )
     FROM x, digits AS z
    WHERE ind>0
      AND NOT EXISTS (
            SELECT 1
              FROM digits AS lp
             WHERE z.z = substr(s, ((ind-1)/9)*9 + lp, 1)
                OR z.z = substr(s, ((ind-1)%9) + (lp-1)*9 + 1, 1)
                OR z.z = substr(s, (((ind-1)/3) % 3) * 3
                        + ((ind-1)/27) * 27 + lp
                        + ((lp-1) / 3) * 6, 1)
         )
  )
SELECT s FROM x WHERE ind=0;
"""
from datafusion import SessionContext
ctx = SessionContext()
ctx.sql(s)

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  1. l1t1 commented on Oct 16, 2026

    @l1t1
    Author

    I got it, in z.z, datafusion regards the first z as a column, not a table, following one is ok

    WITH RECURSIVE
      input(sud) AS (
        VALUES('....754..........8.8.19....3....1.6........34....6817.2.4...6.39......2.53.2.....'), 
        ('3.........5.7.3..8....28.7.7......43...........39.41.54..3..8..1...4....968...2..')
      ),
      digits(z, lp) AS (
        VALUES('1', 1)
        UNION ALL SELECT
        CAST(lp+1 AS TEXT) as z, lp+1 as lp FROM digits WHERE lp<9
      ),
      x(s, ind) AS (
        SELECT sud, instr(sud, '.') FROM input
        UNION ALL
        SELECT
          substr(s, 1, ind-1) || z || substr(s, ind+1),
          instr( substr(s, 1, ind-1) || z || substr(s, ind+1), '.' )
         FROM x, digits AS d
        WHERE ind>0
          AND NOT EXISTS (
                SELECT 1
                  FROM digits AS lp
                 WHERE d.z = substr(s, ((ind-1)/9)*9 + lp, 1)
                    OR d.z = substr(s, ((ind-1)%9) + (lp-1)*9 + 1, 1)
                    OR d.z = substr(s, (((ind-1)/3) % 3) * 3
                            + ((ind-1)/27) * 27 + lp
                            + ((lp-1) / 3) * 6, 1)
             )
      )
    SELECT s FROM x WHERE ind=0;
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